Problem Analysis #11

Gemini 3.5 Flash · Run 1

Correct
22.89s
4,979 toks

API · no tools. This is the prompt and response recorded for this attempt; a full solution may not have been returned.

Problem Statement

Return a single integer only. The problem has been revised so that no final answer is an irrational number, a parameterized expression, a range, a proof, a drawing, a graph, a locus equation, or a region description.

In an isosceles triangle ABCABC with AB=AC=1AB=AC=1, let ss be the smallest radius such that the three disks centered at A,B,CA,B,C cover all three sides. For BAC=π/3\angle BAC=\pi/3, s=1/2s=1/2. For BAC=2π/3\angle BAC=2\pi/3, s=3/2s=\sqrt3/2. Compute the integer

(2s1)+(4s22),(2s_1)+(4s_2^2),

where s1s_1 is the first value and s2s_2 is the second value.

Ground Truth
4
Recorded model response / solution
Reasoning Process

To find the value of the expression (2s1)+(4s22)(2s_1) + (4s_2^2), we use the given values for s1s_1 and s2s_2:

  • The first value is s1=12s_1 = \frac{1}{2} (for BAC=π/3\angle BAC = \pi/3).
  • The second value is s2=32s_2 = \frac{\sqrt{3}}{2} (for BAC=2π/3\angle BAC = 2\pi/3).

Now, we substitute these values into the expression:

  1. Compute 2s12s_1:

    2s1=2(12)=12s_1 = 2 \left(\frac{1}{2}\right) = 1
  2. Compute 4s224s_2^2:

    4s22=4(32)2=4(34)=34s_2^2 = 4 \left(\frac{\sqrt{3}}{2}\right)^2 = 4 \left(\frac{3}{4}\right) = 3
  3. Add the two results:

    (2s1)+(4s22)=1+3=4(2s_1) + (4s_2^2) = 1 + 3 = 4

\boxed{4}

Final Model Output
4

Comparative Analysis (P11) (Average across runs)

Averages use reported measurements only. Missing usage is not treated as zero.

Avg Time Taken

K-EXAONE-236B-A23B
132.8
Gemini 3.5 Flash
18.0
DeepSeek V4 Pro
7.6
GPT-5.5
3.5
Solar Pro 3
2.8
Claude Opus 4.8
2.5
KT Mi:dm 2.0 Base Instruct
1.3

Avg Token Usage

K-EXAONE-236B-A23B
17931.0
Gemini 3.5 Flash
4173.7
KT Mi:dm 2.0 Base Instruct
1188.3
Solar Pro 3
645.3
DeepSeek V4 Pro
578.7
Claude Opus 4.8
413.3
GPT-5.5
351.0
    Tokyo · Problem 11 · Gemini 3.5 Flash | EntropyMath