Problem Analysis #24

KT Mi:dm 2.0 Base Instruct · Run 1

Correct
1.12s
923 toks

API · no tools. This is the prompt and response recorded for this attempt; a full solution may not have been returned.

Problem Statement

Return a single integer only. The problem has been revised so that no final answer is an irrational number, a parameterized expression, a range, a proof, a drawing, a graph, a locus equation, or a region description.

In the complex cubic problem, one endpoint of the possible range of sinθ\sin\theta is 23/2723/27, and the relevant area is 434\sqrt3. Encode the endpoint 23/2723/27 by 23+2723+27, and encode the area by squaring it. Find the sum of the two encoded integers.

Ground Truth
98
Recorded model response / solution
Reasoning Process

To solve the problem, we need to encode the endpoint 2327\frac{23}{27} and the area 434\sqrt{3} as specified, and then find the sum of the encoded integers.

  1. Encode the endpoint 2327\frac{23}{27}:

    • The endpoint is 2327\frac{23}{27}.
    • According to the problem, we encode this by adding the numerator and denominator: 23+27=5023 + 27 = 50.
  2. Encode the area 434\sqrt{3}:

    • The area is 434\sqrt{3}.
    • According to the problem, we square this value: (43)2=16×3=48(4\sqrt{3})^2 = 16 \times 3 = 48.
  3. Sum the two encoded integers:

    • The encoded endpoint is 5050.
    • The encoded area is 4848.
    • The sum of these two integers is 50+48=9850 + 48 = 98.

Thus, the final answer is 98\boxed{98}.

Final Model Output
98

Comparative Analysis (P24) (Average across runs)

Averages use reported measurements only. Missing usage is not treated as zero.

Avg Time Taken

K-EXAONE-236B-A23B
27.1
Gemini 3.5 Flash
4.6
DeepSeek V4 Pro
4.0
GPT-5.5
3.6
Claude Opus 4.8
2.3
Solar Pro 3
2.0
KT Mi:dm 2.0 Base Instruct
0.7

Avg Token Usage

K-EXAONE-236B-A23B
1114.3
KT Mi:dm 2.0 Base Instruct
899.7
Gemini 3.5 Flash
850.3
Solar Pro 3
501.3
DeepSeek V4 Pro
372.7
Claude Opus 4.8
321.7
GPT-5.5
285.7
    Tokyo · Problem 24 · KT Mi:dm 2.0 Base Instruct | EntropyMath