Problem Analysis #17

Claude Opus 4.8 · Run 1

Correct
5.15s
599 toks

API · no tools. This is the prompt and response recorded for this attempt; a full solution may not have been returned.

Problem Statement

Return a single integer only. The problem has been revised so that no final answer is an irrational number, a parameterized expression, a range, a proof, a drawing, a graph, a locus equation, or a region description.

A square number means the square of a nonnegative integer. Let

h(n)=n2+12n12.h(n)=n^2+12n-12.

Find the number of positive integers nn for which h(n)h(n) is a square number.

Ground Truth
3
Recorded model response / solution
Reasoning Process

We need n²+12n-12 = k².

n²+12n-12 = (n+6)²-48 = k².

So (n+6)²-k²=48. (n+6-k)(n+6+k)=48.

Let a=n+6-k, b=n+6+k, ab=48, a+b=2(n+6), same parity.

Both even: a·b=48 with both even. Factor pairs (positive, a≤b): (2,24): sum26, n+6=13, n=7, k=11. Check: 49+84-12=121=11². Yes. (4,12): sum16, n+6=8, n=2, k=4. Check:4+24-12=16=4². Yes. (6,8): sum14, n+6=7, n=1, k=1. Check:1+12-12=1. Yes.

Also negative factors but n positive so n+6 positive, a+b positive. k≥0.

Consider k could make a negative if k>n+6. Then a negative, b positive, product negative ≠48. So both positive.

Both odd: 48 not product of two odds (48 even). No.

So three values: n=1,2,7.

\boxed{3}

Final Model Output
3

Comparative Analysis (P17) (Average across runs)

Averages use reported measurements only. Missing usage is not treated as zero.

Avg Time Taken

K-EXAONE-236B-A23B
86.8
DeepSeek V4 Pro
25.3
GPT-5.5
9.9
Gemini 3.5 Flash
8.8
Solar Pro 3
6.2
Claude Opus 4.8
4.6
KT Mi:dm 2.0 Base Instruct
2.9

Avg Token Usage

K-EXAONE-236B-A23B
10194.7
Gemini 3.5 Flash
2192.0
DeepSeek V4 Pro
1626.7
KT Mi:dm 2.0 Base Instruct
1601.0
Solar Pro 3
1105.7
Claude Opus 4.8
575.3
GPT-5.5
557.7
    Tokyo · Problem 17 · Claude Opus 4.8 | EntropyMath