Let
and consider the upper semicircular arc
Let
and form the closed contour
where is traversed from to , and is traversed from to .\
Suppose the contour integral
where and are positive integers which are relatively prime. Find .
[THOUGHT] We use Cauchy's theorem, noting that the polynomial is entire, making the integral over the closed contour equal to zero. Thus, , implying . For , parametrize as with from to :
-\int_L f(z)\,dz = -\frac{125}{12} $$, with co-prime $p=125$, $q=12$, leading to $p+q = 137$. [/THOUGHT] [PYTHON] # Calculate the real integral from sympy import Symbol, integrate x = Symbol('x') integral_L = integrate(x**2, (x, -5/2, 5/2)) p = int(integral_L.numerator) q = int(integral_L.denominator) result = -(p + q) (p, q, result) [/PYTHON] Final Answer \boxed{137}.[THOUGHT] We use Cauchy's theorem, noting that the polynomial $ f(z) = z^2 $ is entire, making the integral over the closed contour $\Gamma$ equal to zero. Thus, $\oint_\Gamma f(z)\,dz = 0$, implying $\int_C f(z)\,dz = -\int_L f(z)\,dz$. For $L$, parametrize as $f(x) = x^2$ with $x$ from $-5/2$ to $5/2$:-\int_L f(z),dz = -\frac{125}{12} $$, with co-prime , , leading to .
[/THOUGHT]
[PYTHON]
Calculate the real integral
from sympy import Symbol, integrate
x = Symbol('x') integral_L = integrate(x**2, (x, -5/2, 5/2)) p = int(integral_L.numerator) q = int(integral_L.denominator) result = -(p + q)
(p, q, result)
[/PYTHON]
Final Answer \boxed{137}.
[THOUGHT] Analytic computation corrects Python error. The integral equals , hence implies , . Their sum is . Prior AttributeErrors arose from improper result handling, overridden accurately by analysis. [/THOUGHT] \boxed{137}[THOUGHT] Analytic computation corrects Python error. The integral equals , hence implies , . Their sum is . Prior AttributeErrors arose from improper result handling, overridden accurately by analysis. [/THOUGHT] \boxed{137}