In the three-dimensional orthogonal coordinate system , consider the surface defined bywhere and are parameters of the surface , andLet be the region surrounded by the surface , and let be the region satisfying the inequality . Answer the following questions for the surface .
- [I.] Find the unit normal vector oriented inward the region at the point on the surface .
- [II.] Find the area of the portion of the surface included in the region .
- [III.] Find the volume of the overlapping region .
- [IV.] Consider the curve on the surface defined by setting in the parametrization of . Find the curvature of the curve at the point on the curve . Note that, in general, given a three-dimensional curve defined bywith parameter , the curvature of the curve at the point is given byLet be the inward unit normal vector at obtained in {\rm I}. Let be the area obtained in {\rm II}, and let be the overlapping volume obtained in {\rm III}. Let be the curvature at obtained in {\rm IV}.DefineCompute the integer .\
[THOUGHT] Model S is a torus with major radius 2 and minor radius 1. I will:
- Identify parameters for P and compute the inward unit normal by comparing the surface normal to the direction toward the torus centerline.
- Compute the area element |r_θ×r_φ| and integrate over the φ-range where x^2+y^2≤4.
- Compute V∩W via cylindrical coordinates integrating the solid torus inequality with ρ≤2.
- Parametrize curve C by t with θ=φ=t, compute curvature at t=π/2 (point Q), then assemble 𝒦 and simplify to an integer using sympy. [/THOUGHT] [PYTHON] import sympy as sp
Symbols
t = sp.symbols('t', real=True) theta, phi = sp.symbols('theta phi', real=True)
Parametrization of torus S
x = (sp.cos(phi) + 2) * sp.cos(theta) y = (sp.cos(phi) + 2) * sp.sin(theta) z = sp.sin(phi) r = sp.Matrix([x, y, z])
r_theta = sp.diff(r, theta) r_phi = sp.diff(r, phi)
Normal via cross product
N = sp.simplify(r_theta.cross(r_phi)) # not unit
Point P corresponds to theta=pi/4, phi=pi
subsP = {theta: sp.pi/4, phi: sp.pi} P = sp.Matrix([1/sp.sqrt(2), 1/sp.sqrt(2), 0])
N_P = sp.simplify(N.subs(subsP))
Determine inward direction: towards torus centerline circle at same theta, z=0: (2cosθ,2sinθ,0)
centerline_P = sp.Matrix([2sp.cos(sp.pi/4), 2sp.sin(sp.pi/4), 0]) toward_centerline = sp.simplify(centerline_P - P)
Choose sign so that dot(normal, toward_centerline) > 0 for inward
dot_val = sp.simplify(N_P.dot(toward_centerline))
Unit normal candidate
N_P_norm = sp.sqrt(sp.simplify(N_P.dot(N_P))) unit = sp.simplify(N_P / N_P_norm) unit_inward = sp.simplify(unit if dot_val > 0 else -unit) # may not compare symbolically; handle numerically dot_num = float(sp.N(dot_val)) unit_inward = unit if dot_num > 0 else -unit unit_inward_simplified = sp.simplify(unit_inward)
print("N_P:", N_P) print("toward_centerline:", toward_centerline) print("dot_val:", sp.N(dot_val)) print("unit_inward:", unit_inward_simplified)
n1, n2, n3 = [sp.simplify(c) for c in unit_inward_simplified]
II) Area portion where x^2+y^2 <=4 -> (cos phi +2)^2 <=4 -> cos phi <=0
area_element = sp.simplify(sp.sqrt((r_theta.cross(r_phi)).dot(r_theta.cross(r_phi)))) print("area_element simplified:", area_element)
A_S = sp.simplify(sp.integrate(area_element, (phi, sp.pi/2, 3sp.pi/2), (theta, 0, 2sp.pi))) print("A_S:", A_S)
III) Overlapping volume V∩W
rho = sp.symbols('rho', positive=True, real=True) z_sym = sp.symbols('z', real=True)
For rho in [1,2], z bounds +/- sqrt(1-(rho-2)^2)
zmax = sp.sqrt(1-(rho-2)*2) Vov = sp.simplify(sp.integrate(4sp.pirhozmax, (rho, 1, 2))) # 2πρ(2zmax) = 4π ρ zmax print("Vov:", Vov)
IV) curvature of curve C where theta=phi=t
c = sp.Matrix([(sp.cos(t)+2)*sp.cos(t), (sp.cos(t)+2)*sp.sin(t), sp.sin(t)]) c1 = sp.diff(c, t) c2 = sp.diff(c1, t) kappa = sp.simplify(sp.sqrt((c1.cross(c2)).dot(c1.cross(c2))) / (sp.sqrt(c1.dot(c1))**3)) kappa_Q = sp.simplify(kappa.subs(t, sp.pi/2)) print("kappa_Q:", kappa_Q, "numeric:", sp.N(kappa_Q))
Assemble K
K_expr = sp.simplify(999123((Vov/(2sp.pi)) - (A_S/(4sp.pi))) * ((n1+n2)2)/(kappa_Q2) + 7) print("K_expr simplified:", K_expr) print("K_expr numeric:", sp.N(K_expr))
Ensure integer
K_int = sp.nsimplify(K_expr) print("K nsimplify:", K_int) print("Is integer:", K_int.is_integer) print(int(K_int)) [/PYTHON]
[THOUGHT] Using the computed inward normal, area, overlapping volume, and curvature from the Python output, the expression for (\mathcal{K}) simplifies exactly to an integer. [ \boxed{249757} ]