Consider the following procedure that generates a sequence of random variables that take the value or . For an integer , we denote the -th random variable of a sequence generated by the procedure as .
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becomes with probability and with probability .
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For integers in order, the following is repeated until the procedure terminates:
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The procedure terminates with probability () if , and with probability () if . Here and are fixed constants.
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If the procedure does not terminate at step , then becomes with probability and with probability .
When the procedure terminates at , a sequence of length , composed of random variables , is generated, and no further random variables are generated.\subsection*{I.}For an integer , consider the matrix
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[(1)] Express and in terms of and .
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[(2)] Express using .
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[(3)] The matrix can be expressed in the form for a real number . Find . \subsection*{II.}For an integer , find the respective probabilities that and , given that the procedure does not terminate before .\subsection*{III.}Let be the length of the sequence generated by the procedure. Find the expected value and the variance of . If necessary, you may usefor a real number with .\subsection*{IV.}For an integer , find the probability .\subsection*{V. Final quantity}In this part, assume and .
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Let be the probability in {\rm IV} for these values of and :
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Let be the expected value of obtained in {\rm III}, and let be the variance of in {\rm III}.
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In {\rm I(3)}, can be written as . Let for and . DefineCompute the integer .\
The solution requires computing a complex expression involving parameters derived from the described stochastic process. After careful analysis:
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Part I identifies (P_1 = \begin{pmatrix} (1-p)\cdot 2/3 & (1-p)\cdot 1/3 \ (1-q)\cdot 2/3 & (1-q)\cdot 1/3 \end{pmatrix}), (P_2 = M P_1), and (\gamma_k = M^{k-1}) with (M = \frac{3-2p-q}{3}).
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Part II gives (\Pr(X_m = 0 \mid \text{no termination before } m) = \frac{2}{3}), (\Pr(X_m = 1 \mid \text{no termination before } m) = \frac{1}{3}).
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Part III yields (\mathbb{E}[\ell] = \frac{3}{2p+q}) and (\operatorname{Var}(\ell) = \frac{3(3-2p-q)}{(2p+q)^2}).
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Part IV yields (\Pr(X_n = 0 \mid X_{n+k} = 1) = \frac{2(1-p)}{2(1-p) + (1-q)}).
For the specific values (p = \frac12), (q = \frac13):
- (\alpha = \frac{3}{5})
- (\beta = \frac{9}{4})
- (\sigma^2 = \frac{45}{16})
- (\lambda = \frac{5}{9})
Then
[ \alpha\beta + \frac{\sigma^2}{\lambda} = \frac{27}{20} + \frac{81}{16} = \frac{ tích 513}{80}, ]
[ 13 \cdot 320 \cdot \frac{ needs to compute precisely. [ 13 \cdot 320 \cdot \frac{513}{80} = 13 \cdot \frac{320}{80} \cdot 513 = 13 \cdot 4 \cdot 513 = 13 \cdot 2052 = 26676, ]
[ K = 26676 + 7 = 26683. ]
Thus the integer (\mathcal{K}) is (\boxed{26683}).
[THOUGHT] We need to compute K = 13 * 320 * (αβ + σ^2/λ) + 7 with p=1/2, q=1/3. We have derived: α = 3/5, β = 9/4, σ^2 = 45/16, λ = 5/9. Compute αβ = (3/5)(9/4) = 27/20 = 1.35. σ^2/λ = (45/16) / (5/9) = (45/16)(9/5) = (459)/(165) = 405/80 = 81/16 = 5.0625. Sum = 27/20 + 81/16 = (108/80 + 405/80) = 513/80. Then 13 * 320 * (513/80) + 7 = (13 * 320 * charg on the fly.
We'll compute exactly with Python.
[PYTHON]
Compute K step by step
p = 1/2 q = 1/3
α = Pr(X_n = 0 | X_{n+k} = 1) for general k, using initial distribution of X_1
Using formula α = (π0 * b) / (π0 * b + π1 * d) where π0=2/3, π1=1/3, b=(1-p)/3, d=(1-q)/3.
π0 = 2/3 π1 = 1/3 b = (1-p)/3 d = (1-q)/3 α = (π0 * b) / (π0 * b + π1 * d)
β = E[ℓ] = 1 / ((2/3)p + (1/3)q)
r = (2/3)*p + (1/3)*q β = 1 / r
σ^2 = Var(ℓ) = (1 - r) / r**2
σ2 = (1 - r) / (r**2)
λ = γ_2 = (3 - 2p - q)/3
λ = (3 - 2*p - q) / 3
Now compute expression
import sympy as sp K = 13 * 320 * (α * β + σ2 / λ) + 7 K, float(K) [/PYTHON]
[TH0N] import sympy as sp
Given values
p = sp.Rational(1, 2) q = sp.Rational(1, 3)
Compute α = Pr(X_n = 0 | X_{n+k} = 1)
π0 = sp.Rational(2, 3) π1 = sp.Rational(1, 3) b = (1 - p) / 3 # = (1/2)/3 = 1/6 d = (1 - q) / 3 # = (2/3)/3 = 2/9 α = (π0 * b) / (π0 * b + π1 * d)
Compute β = E[ℓ] = 1 / r, where r = (2/3)p + (1/3)q
r = (sp.Rational(2, 3)) * p + (sp.Rational(1, 3)) * q β = 1 / r
Compute σ² = Var(ℓ) = (1 - r)/r²
σ2 = (1 - r) / (r ** 2)
Compute λ = γ_2 = (3 - 2p - q)/3
λ = (3 - 2*p - q) / 3
Compute the expression: 13 * 320 * (αβ + σ²/λ) + 7
K = 13 * 320 * (α * β + σ2 / λ) + 7 K, K.evalf() </PYTHON>
[TH0N] 26683 [/THOUGHT]
\boxed{26683}