Let denote the set of all real numbers. Let and be two complex numbers, where . LetIf the circle has centre and radius , find the value of .\
To solve the problem, we begin by interpreting the given condition:
where and . This is equivalent to:
Step 1: Square Both Sides
Squaring both sides to eliminate the square roots:
Expanding both sides:
-
Left-hand side:
-
Right-hand side:
Now equating both sides:
Bring all terms to one side:
Simplify:
Multiply through by for simplicity:
Step 2: Complete the Square
Divide the entire equation by 3 to normalize the coefficients of and :
Group and complete the square:
- For : x^2 + \frac{2}{3}x = \left(x + \frac{1}{3}\)^2 - \frac{1}{9}
- For : y^2 - \frac{20}{3}y = \left(y - \frac{10}{3}\)^2 - \frac{100}{9}
So the equation becomes:
Combine constants:
Convert to ninths:
Thus, the circle has:
- Center:
- Radius squared:
Step 3: Compute the Desired Expression
We are asked to compute:
Where:
Compute:
Final Answer
[THOUGHT] I need to compute the value of where is the center and is the radius of the circle defined by the equation , with and .
Let me verify the calculations using Python to ensure accuracy: </think>
[THOUGHT] The problem involves finding the value of where the circle is defined by , with and . To solve this, I need to derive the circle equation from the given condition, find its center and radius , and compute the required expression. Let's use Python to perform the symbolic calculations and verify each step. </THOUGHT> [PYTHON] import sympy as sp
Define variables
x, y = sp.symbols('x y')
Define z1 and z2
z1 = 1 + 2j z2 = 0 + 3j
The condition is |x + iy - z1| = 2|x + i*y - z2|
Compute squared magnitudes to avoid square roots
left = (x - 1)**2 + (y - 2)2 right = 4 * (x2 + (y - 3)**2)
Expand and simplify to get the circle equation
equation = sp.expand(left - right) circle_eq = sp.Eq(equation, 0)
Convert to standard circle form by completing the square
Rearrange equation to the form x^2 + y^2 + Dx + Ey + F = 0
A = sp.expand(circle_eq.lhs) print("Circle equation:", A)
Extract coefficients for x^2, y^2, x, y, constant
coeff_x2 = A.coeff(x2) coeff_y2 = A.coeff(y2) coeff_x = A.coeff(x) coeff_y = A.coeff(y) constant = A.coeff(1)
print(f"Coefficients: x^2: {coeff_x2}, y^2: {coeff_y2}, x: {coeff_x}, y: {coeff_y}, constant: {constant}")
Since coefficients of x^2 and y^2 are equal (both -3), divide by -3 to make them 1
if coeff_x2 == -3 and coeff_y2 == -3: A = sp.expand(A / -3) print("After dividing by -3:", A) else: print("Unexpected coefficients for x^2 or y^2")
Now complete the square for x and y terms
The equation is x^2 + y^2 + (2/3)x - (20/3)y + 31/3 = 0 (after dividing by -3)
But let's use the symbolic expression to complete the square
For x: coefficient of x is (2/3), so (x + 1/3)^2 = x^2 + (2/3)x + 1/9
For y: coefficient of y is -(20/3), so (y - 10/3)^2 = y^2 - (20/3)y + 100/9
Adjust the constant term
x_center = -1/3 y_center = 10/3 r_squared = 8/9
Compute 9*(x0 + y0)*r^2
result = 9 * (x_center + y_center) * r_squared print(f"Center: ({x_center}, {y_center})") print(f"r^2: {r_squared}") print(f"9*(x0 + y0)*r^2 = {result}")
Output the result
print("\nFinal answer:", result) [/PYTHON]
[THOUGHT]
Let's carefully analyze the problem. We are given a condition on real numbers and :
with and .
This is the equation of a circle in the complex plane (or the -plane), defined as the set of points whose distance to is twice the distance to .
Step 1: Square Both Sides
We square both sides to eliminate the square root:
Step 2: Expand and Simplify
Left-hand side:
Right-hand side:
Set equal:
Bring all terms to one side:
Divide through by to simplify:
--- of completing the square:
- For :
- For :
So the equation becomes:
Step 3: Identify Circle Parameters
From the standard form of a circle , we identify:
- Center:
- Radius squared:
Step 4: Compute the Desired Expression
We are asked to compute:
Compute: