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This is a Korean CSAT mathematics multiple-choice problem. Solve it and put only the correct choice symbol, one of ①, ②, ③, ④, ⑤, inside \boxed{}.
Problem 28 There are sixteen balls and six empty boxes labeled with the integers 1,2,3,4,5,6. Using a single die, we perform the following experiment. Roll the die once. If the outcome isk, then – ifkis odd, put one ball into each of the boxes labeled 1, 3, and 5; – ifkis even, put one ball into each box whose label is a positive divisor ofk. This experiment is repeated 4 times. After the 4 repetitions, suppose that the sum of the numbers of balls in all six boxes is odd. Under this condition, find the probability that the number of balls in the box labeled 3 is exactly one greater than the number of balls in the box labeled 2. [4 points] ① 1 8 ② 3 16 ③ 1 4 ④ 5 16 ⑤ 3 8 Numerical answer
\boxed{②}
Comparative Analysis (P27) (Average across runs)
Averages use reported measurements only. Missing usage is not treated as zero.